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(0.5x^2)-(4.5x)+3.5=0
We add all the numbers together, and all the variables
(0.5x^2)-(+4.5x)+3.5=0
We get rid of parentheses
0.5x^2-4.5x+3.5=0
a = 0.5; b = -4.5; c = +3.5;
Δ = b2-4ac
Δ = -4.52-4·0.5·3.5
Δ = 13.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4.5)-\sqrt{13.25}}{2*0.5}=\frac{4.5-\sqrt{13.25}}{1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4.5)+\sqrt{13.25}}{2*0.5}=\frac{4.5+\sqrt{13.25}}{1} $
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